If ${\mu }_{0}$ and ${\epsilon }_{0}$ are the permeability and permittivity of free space, respectively, then the dimension of $\left(\frac{1}{{\mu }_{0}{\epsilon }_{0}}\right)$ is : [JEE Main 2025, 2 Apr (Shift 2)]

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YESPYQ · Accepted Answer

Correct answer: c) ${\mathrm{L}}^{2}{\mathrm{T}}^{-2}$. $C=\frac{1}{\sqrt{\mu_0 \varepsilon_0}} \Rightarrow \frac{1}{\mu_0 \varepsilon_0}=C^2=L^2 T^{-2}$

If \({\mu }_{0}\) and \({\epsilon }_{0}\) are the permeability and permittivity of free space, respectively, then the di…

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