A car moving with a speed of 54 km / h takes a turn of radius 20 m . A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take $g=10m/{s}^{2}$ )

[JEE Main 2026, 8 Apr (Shift 2)]

Question

A car moving with a speed of 54 km / h takes a turn of radius 20 m . A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take $g=10m/{s}^{2}$ )

[JEE Main 2026, 8 Apr (Shift 2)]

YESPYQ · Accepted Answer

Correct answer: c) ${\tan }^{-1}(1.125)$. For the pendulum bob in the turning car, $\tan \theta =\frac{{v}^{2}}{rg}$ Given: $v=54\times \frac{5}{18}=15m/s$ So, $\tan \theta =\frac{{15}^{2}}{20\times 10}=1.125$ $\theta ={\tan }^{-1}(1.125)$

A car moving with a speed of 54 km / h takes a turn of radius 20 m . A simple pendulum is suspended from the ceiling of …

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