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Match List - I with List - II. List - I List - II (A) Young's Modulus (I) \(M{L}^{-1}{T}^{-1}\) (B) Torque (II) \(M{L}^{…

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Match List - I with List - II.

List - I List - II
(A) Young's Modulus (I) \(M{L}^{-1}{T}^{-1}\)
(B) Torque (II) \(M{L}^{-1}{T}^{-2}\)
(C) Coefficient of Viscosity (III) \({M}^{-1}{L}^{3}{T}^{-2}\)
(D) Gravitational Constant (IV) \(M{L}^{2}{T}^{-2}\)

Choose the correct answer from the options given below :

[JEE Main 2025, 29 Jan (Shift 2)]

a

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

b

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

c

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

d

(A)-(I), (B)-(III), (C)-(II), (D)-(IV)

✓ Correct answer: a)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Explanation

\(\text{ (A) }[Y]=\frac{F}{A\left(\frac{\Delta ℓ}{ℓ}\right)}=M{L}^{-1}{T}^{-2}\left(\frac{\Delta ℓ}{ℓ}\right.=\text{ Dimensionless })\)

(B) Torque

\((\vec{\tau })=\vec{r}\times \vec{F}=L\times ML{T}^{-2}=M{L}^{2}{T}^{-2}\)

(C) Coefficient of viscosity \(\Rightarrow \frac{F}{A\cdot \frac{dv}{dt}}\)

\(\eta \to Pa\text{ sec. }\\ [\eta ]=\frac{ML{T}^{-2}}{{L}^{2}}\times T=M{L}^{-1}{T}^{-1}\)

\(\text{ (D) Gravitational constant ( }G\text{ ) }\\ [G]=\frac{F\cdot {r}^{2}}{{m}_{1}{m}_{2}}=\frac{ML{T}^{-2}\times {L}^{2}}{{M}^{2}}={M}^{-1}{L}^{3}{T}^{-2}\)

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