Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10. If the binding energy per nucleon for the mass numbers 3,4 and 10 are 5.6 MeV, 7.4 MeV and 6.1 MeV, respectively, then in the process, $∆M{c}^{2}=____MeV$.

[04 April, 2026 (Shift-I)]

Question

Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10. If the binding energy per nucleon for the mass numbers 3,4 and 10 are 5.6 MeV, 7.4 MeV and 6.1 MeV, respectively, then in the process, $∆M{c}^{2}=____MeV$.

[04 April, 2026 (Shift-I)]

YESPYQ · Accepted Answer

Correct answer: c) 2.2. Initial total binding energy is $\begin{matrix}2\times 3\times 5.6+4\times 7.4 & =33.6+29.6 \ & =63.2\mathrm{MeV}\end{matrix}$ Final binding energy is $10\times 6.1=61.0\mathrm{MeV}$ Therefore, $\Delta M{c}^{2}=63.2−61.0=2.2\mathrm{MeV}$

Two nuclei of mass number 3 combine with another nucleus of mass number 4 to yield a nucleus of mass number 10. If the b…

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