JEEMaths

Straight Lines

44 JEE Maths previous year questions on Straight Lines — options free on every question; 4 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ

Let the range of the function \(f(x)=6+16 \cos x \cdot \cos \left(\frac{\pi}{3}-x\right) \cdot \cos \left(\frac{\pi}{3}+x\right)\)\(\sin 3 x \cdot \cos 6 x, x \in R\) be \([\alpha, \beta]\). Then the distance of the point \((\alpha, \beta)\) from the line \(3 x+4 y+12=0\) is :

[JEE Main 2025, 23 Jan (Shift 2)]

a

11

b

10

c

8

d

9

✓ Correct answer: a)

11

Explanation

\(\text{Since,}\cos x.\cos \left(\frac{\pi }{3}-x\right).\cos \left(\frac{\pi }{3}+x\right)\\ =\frac{1}{4}\cos 3x\\ f\left(x\right)=6+16\left(\frac{1}{4}\cos 3x\right)\sin 3x\cdot \cos 6x\\ =6+4\cos 3x\sin 3x\cos 6x\\ =6+\sin 12x\\ \text{Since,  }\sin \text{12x ∈ }\left[-1,1\right]\\ f\left(x\right)\text{∈ }\left[5,7\right]\\ \left(\alpha ,\beta \right)\equiv \left(5,7\right)\\ \text{ distance }=\left|\frac{15+28+12}{5}\right|=11\)

Q2 FREE PREVIEW
PYQ

Consider the lines \(\mathrm{x}(3\lambda +1)+\mathrm{y}(7\lambda +2)=17\lambda +5\), \(\lambda\) being a parameter, all passing through a point \(P\). One of these lines (say \(L\)) is farthest from the origin. If the distance of \(L\)from the point\((3,6)\) is \(d\), then the value of \({d}^{2}\) is

[JEE Main 2025, 3 Apr (Shift 2)]

a

\(20\)

b

\(30\)

c

\(10\)

d

\(15\)

✓ Correct answer: a)

\(20\)

Explanation

Rearrange the given equation by grouping terms with \(\lambda\):

\(x(3\lambda +1)+y(7\lambda +2)−17\lambda −5=0\)

\(\lambda (3x+7y−17)+(x+2y−5)=0\)

  1. \(x+2y−5=0\Rightarrow x=5−2y\)
  2. \(3x+7y−17=0\)

Substitute (1) into (2): \(3(5−2y)+7y−17=0\) \(15−6y+7y−17=0\) \(y−2=0\Rightarrow y=2\)

Then, \(x=5−2(2)=1\). So, the fixed point is \(P(1,2)\).

  • Slope of \(OP=\frac{2−0}{1−0}=2\).
  • Therefore, the slope of line \(L\) is perpendicular, which is \(−\frac{1}{2}\).

Equation of line \(L\) passing through \((1,2)\) with slope \(−\frac{1}{2}\)

: \(y−2=−\frac{1}{2}(x−1)\) \(2y−4=−x+1\) \(x+2y−5=0\)

Find the perpendicular distance \(d\) from point \((3,6)\) to line \(x+2y−5=0\):

\(d=\frac{\mathrm{∣}1(3)+2(6)−5\mathrm{∣}}{\sqrt{{1}^{2}+{2}^{2}}}\) \(d=\frac{\mathrm{∣}3+12−5\mathrm{∣}}{\sqrt{5}}=\frac{10}{\sqrt{5}}\)

Square both sides to find \({d}^{2}\): \({d}^{2}=\frac{100}{5}=20\)

Q3 FREE PREVIEW
PYQ

If the images of the points \(\mathbf{A}(1,3), \mathbf{B}(3,1)\) and \(\mathbf{C}(2,4)\) in the line \(x+2 y=4\) are D, E and F respectively, then the centroid of the triangle DEF is

a

\(\left(\frac{2}{3},0\right)\)

b

\(\left(\frac{5}{3},0\right)\)

c

\(\left(\frac{1}{3},0\right)\)

d

none of these

✓ Correct answer: a)

\(\left(\frac{2}{3},0\right)\)

Explanation

The mirror line is \(x+2 y-4=0\)
image of \(\mathrm{A}(1,3)\) is \(\frac{x-1}{1}=\frac{y-3}{2}=-2\left(\frac{1+6-4}{5}\right)\)
image of \(\mathrm{B}(3,1)\) is \(\frac{x-3}{1}=\frac{y-1}{2}=-2\left(\frac{3+2-4}{5}\right)\)
image of \((2,4)\) is \(\frac{x-2}{1}=\frac{y-4}{2}=-2\left(\frac{2+8-4}{5}\right)\)

So \(D=\left(-\frac{1}{5}, \frac{3}{5}\right), E=\left(\frac{13}{5}, \frac{1}{5}\right), F=\left(\frac{-2}{5}, \frac{-4}{5}\right)\)
Centroid \(=\left(\frac{\frac{-1}{5}+\frac{13}{5} -\frac{2}{5}}{3}, \frac{\frac{3}{5}+\frac{1}{5}-\frac{4}{5}}{3}\right)\)
\(=\left(\frac{10}{15}, 0\right)=\left(\frac{2}{3}, 0\right)\)

Q4 FREE PREVIEW
PYQ

If the locus of the point, whose distances from the points \((2,1)\) and \((1,3)\) are in the ratio \(5: 4\), is \(a x^2+b y^2+c x y+d x+e y+170=0\), then the value of \(a^2+2 b+3 c+4 d+e\) is equal to:

[JEE Main 2024, 6 Apr (Shift 2)]

a

\(37\)

b

\(5\)

c

\(-27\)

d

\(437\)

✓ Correct answer: a)

\(37\)

Explanation

Let point be \(\mathrm{P}(\mathrm{x}, \mathrm{y})\)

As per the question:

\(\frac{\sqrt{{\left(x-2\right)}^{2}+{\left(y-1\right)}^{2}}}{\sqrt{{\left(x-1\right)}^{2}+{\left(y-3\right)}^{2}}}=\frac{5}{4}\)

\(\Rightarrow \frac{{\left(x-2\right)}^{2}+{\left(y-1\right)}^{2}}{{\left(x-1\right)}^{2}+{\left(y-3\right)}^{2}}=\frac{25}{16}\)

\(\Rightarrow 16\left({x}^{2}-4x+4+{y}^{2}-2y+1\right)\)\(=25\left({x}^{2}-2x+1+{y}^{2}-6y+9\right)\)
\(\Rightarrow 9 x^2+9 y^2+14 x-118 y+170=0\)

Comparing with \(a x^2+b y^2+c x y+d x+e y+170=0\)

\(a=9, b=9, c=0, d=14, e=-118\)

Now,
\(a^2+2 b+3 c+4 d+e\)\(=81+18+0+56-118\)
\(=155-118=37\)

Q5
PYQ

Let the triangle \(P Q R\) be the image of the triangle with vertices \((1,3),(3,1)\) and \((2,4)\) in the line \(x+2 y=2\). If the centroid of \(\Delta PQR\) is the point \((\alpha, \beta)\), then \(15(\alpha-\beta)\) is equal to :

[JEE Main 2025, 22 Jan (Shift 1)]

a

24

b

19

c

21

d

22

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Q6
PYQ

A triangle \(A B C\) have sides \(x+y=11 ; 2 x+3 y=29\) and \(x+2y=16\) such that a point \(P\left(\frac{11}{2}, \alpha\right)\) lies on or inside the triangle find the product of maximum and minimum value of " \(\alpha\) ".

a

29.8

b

31.2

c

31.8

d

32

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Q7
PYQ

Let \({}^{n}C_{r-1}=28,{}^{n}C_{r}=56\text{ and }{}^{n}C_{r+1}=70\). Let \(\mathrm{A}(4\cos t,4\sin t),\mathrm{B}(2\mathrm{sint},-2\mathrm{cost})\)\(\text{ and }C\left(3r-n,{r}^{2}-n-1\right)\) be the vertices of a triangle \(ABC\), where \(t\) is a parameter. If \((3x-1{)}^{2}+(3y{)}^{2}=\alpha ,\) is the locus of the centroid of triangle \(ABC\), then\(\alpha\)equals:

[JEE Main 2025, 28 Jan (Shift 1)]

a

20

b

8

c

6

d

18

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Q8
PYQ

Let the line \({L}_{1}:x+3=0\) intersect the lines \({L}_{2}:x-y=0\) and \({L}_{3}:3x+y=0\) at the points \(A\) and \(B,\) respectively. Let the bisector of the obtuse angle between the lines \({L}_{2}\text{and}{L}_{3}\) intersect the line \({L}_{1}\) at the point \(C.\) Then \(B{C}^{2}:A{C}^{2}\) is equal to:

[JEE Main 2026, 4 Apr (Shift 1)]

a

\(5:1\)

b

\(1:5\)

c

\(2:3\)

d

\(3:2\)

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Q9
PYQ

Two sides of isoceles triangle are \(x+2y=4\) and \(x+y=4\). Then the sum of all possible values of \(m\) where \(m\) is slope of 3rd side,is

a

\(\frac{3}{2}\)

b

\(\frac{2}{3}\)

c

\(-\frac{3}{2}\)

d

\(-\frac{2}{3}\)

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Q10
PYQ

A triangle \(A B C\) have sides \(x+y=11 ; 2 x+3 y=29\) and \(x+2y=16\) such that a point \(P\left(\frac{11}{2}, \alpha\right)\) lies on or inside the triangle find the product of maximum and minimum value of " \(\alpha\) ".

a

29.8

b

31.2

c

31.8

d

32

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Q11
PYQ

The distance from the origin to the image of \((1,1)\) with respect to the line \(x+y+5=0\) is:

a

\(7 \sqrt{2}\)

b

\(3 \sqrt{2}\)

c

\(6 \sqrt{2}\)

d

\(4 \sqrt{2}\)

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Q12
PYQ

Two sides of isoceles triangle are \(x+2y=4\) and \(x+y=4\). Then the sum of all possible values of \(m\) where \(m\) is slope of 3rd side,is

a

\(\frac{3}{2}\)

b

\(\frac{2}{3}\)

c

\(-\frac{3}{2}\)

d

\(-\frac{2}{3}\)

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Q13
PYQ

The distance from the origin to the image of \((1,1)\) with respect to the line \(x+y+5=0\) is:

a

\(7 \sqrt{2}\)

b

\(3 \sqrt{2}\)

c

\(6 \sqrt{2}\)

d

\(4 \sqrt{2}\)

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Q14
PYQ

If the images of the points \(\mathbf{A}(1,3), \mathbf{B}(3,1)\) and \(\mathbf{C}(2,4)\) in the line \(x+2 y=4\) are D, E and F respectively, then the centroid of the triangle DEF is (24 Jan, Shift I, Memory Based)

a

\(\left(\frac{2}{3},0\right)\)

b

\(\left(\frac{5}{3},0\right)\)

c

\(\left(\frac{1}{3},0\right)\)

d

none of these

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Q15
PYQ

Let the triangle \(P Q R\) be the image of the triangle with vertices \((1,3),(3,1)\) and \((2,4)\) in the line \(x+2 y=2\). If the centroid of ΔPQR is the point \((\alpha, \beta)\), then \(15(\alpha-\beta)\) is equal to :

a

24

b

19

c

21

d

22

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Q16
PYQ

Let the range of the function

\(f(x)=6+16 \cos x \cdot \cos \left(\frac{\pi}{3}-x\right) \cdot \cos \left(\frac{\pi}{3}+x\right)\)\(\sin 3 x \cdot \cos 6 x, x \in R\)

be \([\alpha, \beta]\). Then the distance of the point \((\alpha, \beta)\) from the line \(3 x+4 y+12=0\) is :

[JEE Main 2025, 23 Jan (Shift 2)]

a

11

b

10

c

8

d

9

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Q17
PYQ

Let the lines \(3x-4y-\alpha =0,8x-11y-33=0\) and \(2x-3y+\lambda =0\) be concurrent. If the image of the point \((1, 2)\) in the line \(2x-3y+\lambda =0\) is \(\left(\frac{57}{13}, \frac{-40}{13}\right)\), then \(|\alpha \lambda|\) is equal to:

[JEE Main 2025, 24 Jan (Shift 1)]

a

84

b

91

c

113

d

101

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Q18
PYQ

Let \(a\) be the length of a side of a square OABC with O being the origin. Its side OA makes an acute angle \(\alpha\) with the positive x-axis and the equations of its diagonals are \((\sqrt{3}+1)x+(\sqrt{3}-1)y=0\) and \((\sqrt{3}-1)x-(\sqrt{3}+1)y+8\sqrt{3}=0\). Then \({a}^{2}\) is equal to

[JEE Main 2025, 8 Apr (Shift 1)]

a

\(48\)

b

\(32\)

c

\(16\)

d

\(24\)

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Q19
PYQ

A line passing through the point \(\mathrm{P}(\mathrm{a},0)\)makes an acute angle \(\alpha\) with the positive x -axis. Let this line be rotated about the point P through an angle \(\frac{\alpha }{2}\) in the clock-wise direction. If in the new position, the slope of the line is \(2-\sqrt{3}\) and its distance from the origin is \(\frac{1}{\sqrt{2}}\), then the value of \(3{\mathrm{a}}^{2}{\tan }^{2}\alpha -2\sqrt{3}\) is

[JEE Main 2025, 8 Apr (Shift 1)]

a

4

b

6

c

5

d

8

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Q20
PYQ

The image of a point \(A(3,8)\) in the line \(x+3y-7=0\), is

a

\((-1,-4)\)

b

\((-3,-8)\)

c

\((1,-4)\)

d

(3, 8)

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Q21
PYQ

let the equation \(x(x+2)(12-k)=2\) have equal roots. Then the distance of the point \(\left(k,\frac{k}{2}\right)\) from the line \(3x+4y+5=0\) is

[JEE Main 2025, 3 Apr (Shift 2)]

a

\(15\)

b

\(5\sqrt{3}\)

c

\(15\sqrt{5}\)

d

\(12\)

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Q22
PYQ

If \(p\) and \(q\) are the length of the perpendiculars from the origin on the lines \(\text{xcosec}\alpha - ysec\alpha = k\ cot2\alpha\) and \(\text{xsin}\alpha + ycos\alpha = ksin2\alpha\) respectively, then \(k^{2}\) is equal to?

[JEE Main 2021, 31 Aug (Shift 1)]

a

\(p^{2} + 2q^{2}\)

b

\(2p^{2} + q^{2}\)

c

\(p^{2} + 4q^{2}\)

d

\(4p^{2} + q^{2}\)

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Q23
PYQ

What is the distance between the straight lines \(3x+4y=9\) and \(6x+8y=15?\)

a

\(\frac{3}{2}\)

b

\(\frac{3}{10}\)

c

6

d

5

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Q24
PYQ

Let \(A(a, 0), B(b, 2 b+1)\) and \(C(0, b), b \neq 0,|b| \neq 1\), be points such that the area of \(\triangle ABC\) is 1sq. unit, then the sum of all possible values of a is

[JEE Main 2021, 27 Aug (Shift 2)]

a

\(\frac{2 b^2}{b+1}\)

b

\(\frac{-2 b^2}{b+1}\)

c

\(\frac{-b^2}{b+1}\)

d

\(\frac{-2 b^2}{b-1}\)

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Q25
PYQ

If the coordinates of the points A and B be (3, 3) and (7, 6), then the length of the portion of the line AB intercepted between the axes is

a

\(\frac{5}{4}\)

b

\(\frac{\sqrt{10}}{4}\)

c

\(\frac{\sqrt{13}}{3}\)

d

None of these

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Q26
PYQ

Let \((\alpha, \beta)\) be the centroid of the triangle formed by the lines \(15 x-y=82,6 x-5 y=-4\) and \(9 x+4 y=17\). Then \(\alpha\) \(+2 \beta\) and \(2 \alpha-\beta\) are the roots of the equation

[JEE Main 2023, 13 Apr (Shift 2)]

a

\(x^2-7 x+12=0\)

b

\(x^2-13 x+42=0\)

c

\(x^2-14 x+48=0\)

d

\(x^2-10 x+25=0\)

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Q27
PYQ

What is the angle between the two straight lines \(y=(2-\sqrt{3}) x+5\) and \(y=(2+\sqrt{3}) x-7 ?\)

a

\(60^{\circ}\)

b

\(45^{\circ}\)

c

\(30^{\circ}\)

d

\(15^{\circ}\)

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Q28
PYQ

Let \(A(a, 0), B(b, 2 b+1)\) and \(C(0, b), b \neq 0,|b| \neq 1\), be points such that the area of \(\triangle ABC\) is 1sq. unit, then the sum of all possible values of \(a\) is

[JEE Main 2021, 27 Aug (Shift 2)]

a

\(\frac{2 b^2}{b+1}\)

b

\(\frac{-2 b^2}{b+1}\)

c

\(\frac{-b^2}{b+1}\)

d

\(\frac{-2 b^2}{b+1}\)

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Q29
PYQ

The combined equation of the two lines \(a x+b y+c=0\) and \(a^{\prime} x+b^{\prime} y+c^{\prime}=0\) can be written as \((a x+b y+c)\left(a^{\prime} x+\right.\) \(\left.b^{\prime} y+c^{\prime}\right)=0\) .The equation of the angle bisectors of the lines represented by the equation \(2 x^2+x y-3 y^2=0\) is

[JEE Main 2023, 1 Feb (Shift 1)]

a

\(3 x^2+5 x y+2 y^2=0\)

b

\(x^2-y^2+10 x y=0\)

c

\(3 x^2+x y-2 y^2=0\)

d

\(x^2-y^2-10 x y=0\)

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Q30
PYQ

The points \(\ (0,7,10),(-1,6,6) \) and \(\ (-4,9,6) \) form

a

a right angled isosceles triangle

b

a scalene triangle

c

a right angled triangle

d

an equilateral triangle

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Q31
PYQ

A light ray emits from the origin making an angle \(30^{\circ}\) with the positive \(x\)-axis. After getting reflected by the line \(x+y=1\), if this ray intersects \(x\)-axis at \(Q\), then the abscissa of \(Q\) is

[JEE Main 2023, 29 Jan (Shift 1)]

a

\(\frac{2}{(\sqrt{3}-1)}\)

b

\(\frac{2}{3+\sqrt{3}}\)

c

\(\frac{2}{3-\sqrt{3}}\)

d

\(\frac{\sqrt{3}}{2(\sqrt{3}+1)}\)

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Q32
PYQ

The set of all possible values of \(\theta\) in the interval \((0, \pi)\) for which the points \((1,2)\) and \((\sin \theta, \cos \theta)\) lie on the same side of the line \(x+y=1\) is:


[JEE Main 2020, 2 Sep (Shift 2)]

a

\(\left(0, \frac{\pi}{2}\right)\)

b

\(\left(\frac{\pi}{4}, \frac{3 \pi}{4}\right)\)

c

\(\left(0, \frac{\pi}{4}\right)\)

d

\(\left(0, \frac{3 \pi}{4}\right)\)

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Q33
PYQ

Statement-1 : If the general equation \(x^2+y^2+2 x y+2 g x+2 f y+4=0\) represents a pair of real lines then \(|g| \geq 2\).
Statement-2 : The equation \(\mathrm{ax}^2+2 \mathrm{hxy}+\mathrm{by}^2+2 \mathrm{gx}+2 \mathrm{fy}+\mathrm{c}=0\) represents pair of real lines if \(abc +2 \mathrm{fgh}-\mathrm{af}^2-\mathrm{bg}^2-\mathrm{ch}^2=0\).

a

Statement -1 is false, Statement- 2 is true

b

Statement -1 is true, Statement-2 is true; Statement -2 is a correct explanation for Statement-1

c

Statement -1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1

d

Statement -1 is true, Statement- 2 is false

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Q34
PYQ

A man is walking on a straight line. The arithmetic mean of the reciprocals of the intercepts of this line on the coordinate axis is \( \frac{1}{4} \). Three stones, \( A, B \) and \( C \) are placed at the point \( (1,1),(2,2) \) and \( (4,4) \) respectively. Then which of these stones is/are on the path of the man

[JEE Main 2021, 24 Feb (Shift 1)]

a

\( B \) only

b

\( A \) only

c

All of three

d

C only

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Q35
PYQ

Let \(a, b, c\) be in arithmetic progression. Let the centroid of the triangle with vertices \((a, c),(2, b)\) and \((a, b)\) be \(\left(\frac{10}{3}, \frac{7}{3}\right)\). If \(\alpha, \beta\) are the roots of the equation \(a x^2+b x+1=0\), then the value of \(\alpha^2+\beta^2-\alpha \beta\) is:

[JEE Main 2021, 24 Feb (Shift 2)]

a

\(\frac{71}{256}\)

b

\(-\frac{69}{256}\)

c

\(\frac{69}{256}\)

d

\(-\frac{71}{256}\)

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Q36
PYQ

If \(p\) and \(q\) are the length of the perpendiculars from the origin on the lines \(x \operatorname{cosec} \alpha-y \sec \alpha=k \cot 2 \alpha\) and \(x \sin \alpha+y \cos \alpha=k \sin 2 \alpha\) respectively, then \(k^2\) is equal to?

[JEE Main 2021, 31 Aug (Shift 1)]

a

\(p^{2} + 2q^{2}\)

b

\(2p^{2} + q^{2}\)

c

\(p^{2} + 4q^{2}\)

d

\(4p^{2} + q^{2}\)

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Q37
PYQ

The distance between the parallel lines \(\ 3 x-4 y+7=0 \) and \(\ 3 x-4 y+5=0 \) is \(\ \frac{a}{b} \). Value of \(\ a+b\) is

a

2

b

5

c

7

d

3

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Q38
PYQ

Consider a triangle Δ whose two sides lie on the x-axis and the line x + y + 1 = 0. If the orthocentre of Δ is (1, 1), then the equation of the circle passing through the vertices of the triangle Δ is

a

x2 + y2 – 3x + y = 0

b

x2 + y2 + x + 3y = 0

c

x2 + y2 + 2y – 1 = 0

d

x2 + y2 + x + y = 0

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Q39
PYQ

If \(\mathrm{p}\) and \(\mathrm{q}\) are the lengths of the perpendiculars from the origin on the lines.

\(x \operatorname{cosec} \alpha-y \sec \alpha=k \cot 2 \alpha\) and \(x \sin \alpha+y \cos \alpha=k \sin\) \(2 \alpha\) respectively, then \(k^{2}\) is equal to:

[JEE Main 2021, 31 Aug (Shift 1)]

a

\(p^{2}+2 q^{2}\)

b

\(4 p^{2}+q^{2}\)

c

\(p^{2}+4 q^{2}\)

d

\(2 p^{2}+q^{2}\)

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Q40
PYQ

Let the equation of the pair of lines, \(y=p x\) and \(y=q x\), can be written as \((y-p x)(y-q x)=0\). Then the equation of the pair of the angle bisectors of the lines \(x^{2}-4 x y-5 y^{2}=0\) is:

[JEE Main 2021, 25 Jul (Shift 2)]

a

\(x^{2}-3 x y+y^{2}=0\)

b

\(x^{2}+3 x y-y^{2}=0\)

c

\(x^{2}-3 x y-y^{2}=0\)

d

\(x^{2}+4 x y-y^{2}=0\)

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Q41
PYQ

The number of integral values of \( m \) so that the abscissa of point of intersection of lines \( 3 x+4 y \) \( =9 \) and \( y=m x+1 \) is also an integer, is :

[JEE Main 2021, 18 Mar (Shift 1)]

a

1

b

2

c

3

d

0

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Q42
PYQ

The equation of one of the straight lines which passes through the point \((1,3)\) and makes an angle \(\tan ^{-1}(\sqrt{2})\) with the straight line \(y+1=3 \sqrt{2} x\) is

a

\(4 \sqrt{2} x+5 y-(15+4 \sqrt{2})=0\)

b

\(5 \sqrt{2} x+4 y-(15+4 \sqrt{2})=0\)

c

\(4 \sqrt{2} x+5 y-4 \sqrt{2}-0\)

d

\(4 \sqrt{2} x-5 y-(5+4 \sqrt{2})=0\)

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Q43
PYQ

If the perpendicular bisector of the line segment joining the points \(\mathrm{P}(1,4)\) and \(\mathrm{Q}(\mathrm{k},3)\) has \(y\)-intercept equal to \(-4,\) then a value of \(k\) is :

[JEE Main 2020, 4 Sep (Shift 2)]

a

\( \sqrt{14} \)

b

\( \sqrt{15} \)

c

\( -4 \)

d

\( -2 \)

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Q44
PYQ

If the system of equations
\[\begin{aligned}& x+2 y+3 z=3 \\& 4 x+3 y-4 z=4 \\& 8 x+4 y-\lambda z=9+\mu\end{aligned}\]
has infinitely many solutions, then the ordered pair \((\lambda, \mu)\) is equal to

a

\(\left(\frac{72}{5}, \frac{21}{5}\right)\)

b

\(\left(\frac{-72}{5}, \frac{-21}{5}\right)\)

c

\(\left(\frac{72}{5}, \frac{-21}{5}\right)\)

d

\(\left(\frac{-72}{5}, \frac{21}{5}\right)\)

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