JEEChemistry

The Solid State

27 JEE Chemistry previous year questions on The Solid State — options free on every question; 3 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ
Most crystals show good cleavage because their atoms, ions or molecules are
aweakly bonded together
bstrongly bonded together
cspherically symmetrical
darranged in planes
✓ Correct answer: d) arranged in planes
ExplanationCleavage in crystals refers to the tendency of a crystal to break along specific planes of weakness.This happens because the arrangement of atoms, ions, or molecules in a crystal lattice creates planes where the bonding forces are weaker compared to other directions.Weak bonding along specific planes allows easy cleavage.Strong bonding within the planes keeps the structure intact in other directions.
Q2 FREE PREVIEW
PYQ

In a metal deficient oxide sample, \({M}_{X}{Y}_{2}{O}_{4}(M\) and \(Y\) are metals), \(M\) is present in both +2 and +3 oxidation states and \(Y\) is in +3 oxidation state. If the fraction of \({M}^{2+}\) ions present in \(M\) is \(\frac{1}{3}\), the value of \(X\) is _______.

JEE Advanced 2024, Paper-1]

a

0.25

b

0.33

c

0.67

d

0.75

✓ Correct answer: d)

0.75

Explanation

(D)

Q3 FREE PREVIEW
PYQ

In a metal deficient oxide sample, MXY2O4(M and Y are metals), M is present in both +2 and +3 oxidation states and Y is in +3 oxidation state. If the fraction of M2+ ions present in M is \(\frac{1}{3}\), the value of X is _______.

[JEE Advanced 2024, Paper-2]

a

0.25

b

0.33

c

0.67

d

0.75

✓ Correct answer: d)

0.75

Explanation

Formula: MₓY₂O₄.
M exists as M²⁺ and M³⁺, Y is +3.
Fraction of M²⁺ = 1/3.

Total M per formula = x.
M²⁺ ions = (1/3)x → charge = 2·(1/3)x = (2/3)x.
M³⁺ ions = (2/3)x → charge = 3·(2/3)x = 2x.
Y³⁺ ions = 2 → charge = 2·3 = 6.
O²⁻ ions = 4 → charge = 4·(−2) = −8.

Charge neutrality: (2/3)x + 2x + 6 − 8 = 0
⇒ (8/3)x − 2 = 0 ⇒ (8/3)x = 2 ⇒ x = 6/8 = 0.75.

Q4
PYQ

In a metal deficient oxide sample, \({M}_{X}{Y}_{2}{O}_{4}(M\) and \(Y\) are metals), \(M\) is present in both +2 and +3 oxidation states and \(Y\) is in +3 oxidation state. If the fraction of \({M}^{2+}\) ions present in \(M\) is \(\frac{1}{3}\), the value of \(X\) is _______.

[JEE Advanced 2024, Paper-2]

a

0.25

b

0.33

c

0.67

d

0.75

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Q5
PYQ

Which of the following is not a semiconductor?

a

Si

b

Graphite

c

CuO

d

Ge

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Q6
PYQ

Ga (atomic mass \( 70 \mathrm{u} \) ) crystallizes in a hexagonal close packed structure. The total number of voids in \( 0.581 \mathrm{~g} \) of \( \mathrm{Ga} \) is__________ \( \times 10^{21} \). (Round off to the Nearest Integer). [Given : \( \left.\mathrm{N}_{\mathrm{A}}=6.023 \times 10^{23}\right] \)

[JEE Main 2021, 16 Mar (Shift 2)]

a

14

b

15

c

16

d

17

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Q7
PYQ

A compound is formed by two elements \(X\) and \(Y\). The element \(Y\) forms cubic close packed arrangement and element X occupies one third of the tetrahedral voids. What is the formula of the compound?

[JEE Main 2023, 6 Apr (Shift 1)]

a

\(X_2 Y_3\)

b

\(XY\)

c

\(X _3 Y\)

d

\(XY _3\)

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Q8
PYQ

Sodium metal crystallizes in a body centred cubic lattice with unit cell edge length of 4 Å.The radius of sodium atom is _____\(\times 10^{-1}\) Å (Nearest Integer)

[JEE Main 2023, 13 Apr (Shift 2)]

a

12

b

13

c

14

d

17

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Q9
PYQ

In a binary compound, atoms of element \( \mathrm{A} \) form a hcp structure and those of element M occupy \( 2 / 3 \) of the tetrahedral voids of the hcp structure. The formula of the binary compound is

a

\( \mathrm{M}_{2} \mathrm{~A}_{3} \)

b

\( \mathrm{M}_{4} \mathrm{~A}_{3} \)

c

\( \mathrm{M}_{4} \mathrm{~A} \)

d

\( \mathrm{MA}_{3} \)

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Q10
PYQ

Iron oxide \(FeO\), crystallises in a cubic lattice with a unit cell edge length of 5.0 Å. If density of the \(FeO\) in the crystal is \(4.0 g cm ^{-3}\), then the number of \(FeO\) units present per unit cell is______ (Nearest Integer)

Given: Molar mass of Fe and \(O\) is 56 and 16 g/mol respectively
\({N}_{A}=6.0\times {10}^{23}mo{l}^{-1}\)

[JEE Main 2023, 30 Jan (Shift 2)]

a

1

b

2

c

3

d

4

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Q11
PYQ

A hard substance melts at high temperature and is an insulator in both solid and in molten state. This solid is most likely to be a/an

a

Metallic solid

b

Ionic solid

c

Molecular solid

d

Covalent solid

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Q12
PYQ

An element crystallises in a face-centred cubic (fcc) unit cell with cell edge a. The distance between the centres of two nearest octahedral voids in the crystal lattice is

[JEE Main 2020, 5 Sep (Shift 2)]

a

\(\mathrm{a}\)

b

\(\sqrt{2}\mathrm{a}\)

c

\(\frac{\mathrm{a}}{\sqrt{2}}\)

d

\(\frac{\mathrm{a}}{2}\)

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Q13
PYQ

Which of the following expressions is correct in case of a \(CsCl\) unit cell (edge length'a')?

[JEE Main 2023, 15 Apr (Shift 1)]

a

\(r _{ Cs ^{+}}+ r _{ Cl ^{-}}=\frac{ a }{\sqrt{2}}\)

b

\(r _{ Cs+ }+ r _{ Cl }= a\)

c

\(r _{ Cs ^{+}}+ r _{ Cl ^{-}}=\frac{\sqrt{3}}{2} a\)

d

\(r _{ Cs ^{+}}+ r _{ Cl ^{-}}=\frac{ a }{2}\)

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Q14
PYQ

The correct relationship between unit cell edge length ' \(a\) ' and radius of sphere ' \(r\) ' for face-centred and body centred cubic structures respectively are:

[JEE Main 2023, 10 Apr (Shift 2)]

a

\(r=2 \sqrt{2} a \text { and } \sqrt{3} r=4 a\)

b

\(r =2 \sqrt{2} a \text { and } 4 r =\sqrt{3} a\)

c

\(2 \sqrt{2} r = a \text { and } 4 r =\sqrt{3} a\)

d

\(2 \sqrt{2} r = a \text { and } \sqrt{3} r =4 a\)

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Q15
PYQ

A metal M forms hexagonal close-packed structure. The total number of voids in \(0.02 \mathrm{~mol}\) of it is ............\(\times 10^{21}\)(Nearest integer). (Given \(\mathrm{N}_{\mathrm{A}}=6.02 \times 10^{23}\) )

[JEE Main 2023, 29 Jan (Shift 2)]

a

34

b

35

c

36

d

37

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Q16
PYQ

A cubic solid is made up of two elements \(X\) and \(Y\). Atoms of \(X\) are present on every alternate corner and one at the center of cube. Y is at \(\frac{1}{3}\) of the total faces. The empirical formula of the compound is

a

\(X_2 Y_{1.5}\)

b

\(X _{3} Y_{2}\)

c

\(X Y_{2.5}\)

d

\(X_{1.5} Y_2\)

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Q17
PYQ

A diatomic molecule X2 has a body-centred cubic (bcc) structure with a cell edge of 300 pm. The density of the molecule is 6.17 g cm–3. The number of molecules present in 200 g of X2 is:

[Avogadro constant (NA) = 6 × 1023]

[JEE Main 2020, 5 Sep (Shift 1)]

a

\(40 N _{ A }\)

b

\(4 N _{ A }\)

c

\(2 N _{ A }\)

d

\(8 N _{ A }\)

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Q18
PYQ

An atomic substance \(A\) of molar mass \(12 g mol ^{-1}\) has a cubic crystal structure with edge length of \(300 pm\). The no. of atoms present in one unit cell of \(A\) is_______ (Nearest Integer) Given the density of \(A\) is \(3.0 g mL ^{-1}\) and \(N _{ A }=6.02 \times\) \(10^{23} mol ^{-1}\)

[JEE Main 2023, 11 Apr (Shift 1)]

a

4

b

3

c

2

d

1

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Q19
PYQ

A diatomic molecule X2 has a body-centred cubic (bcc) structure with a cell edge of 300 pm. The density of the molecule is 6.17 g cm–3. The number of molecules present in 200 g of X2 is:

[Avogadro constant (NA) = 6 × 1023]

a

\(40 N _{ A }\)

b

\(4 N _{ A }\)

c

\(2 N _{ A }\)

d

\(8 N _{ A }\)

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Q20
PYQ

Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is:

a

\({\mathrm{A}}_{2}{\mathrm{BO}}_{4}\)

b

\({\mathrm{AB}}_{2}{\mathrm{O}}_{4}\)

c

\({\mathrm{A}}_{2}{\mathrm{B}}_{2}\mathrm{O}\)

d

\({\mathrm{A}}_{4}{\mathrm{B}}_{2}\mathrm{O}\)

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Q21
PYQ

Number of crystal systems from the following where body centred unit cell can be found, is

Cubic, tetragonal, orthorhombic, hexagonal, rhombohedral, monoclinic, triclinic

[JEE Main 2023, 6 Apr (Shift 2)]

a

2

b

3

c

1

d

4

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Q22
PYQ

A certain element crystallises in a bcc lattice of unit cell edge length 27 Å. If the same element under the same conditions crystallises in the fcc lattice, the edge length of the unit cell (in Å) will be ______. Assume each lattice point has a single atom. Given: √3 = 1.73, √2 = 1.41

a

33 Å

b

21 Å

c

16 Å

d

49 Å

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Q23
PYQ

An element crystallises in a face-centred cubic (fcc) unit cell with cell edge \(a\). The distance between the centres of two nearest octahedral voids in the crystal lattice is:

a

\(\frac{a}{\sqrt{2}}\)

b

\(a\)

c

\(\frac{a}{2}\)

d

\(\sqrt{2}a\)

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Q24
PYQ

A cubic solid is made up of two elements \(X\) and \(Y\). Atoms of \(X\) are present on every alternate corner and one at the center of cube. Y is at \(\frac{1}{3}\) of the total faces. The empirical formula of the compound is

[JEE Main 2023, 25 Jan (Shift 1)]

a

\(X_2 Y_{1.5}\)

b

\(X _{3} Y_{2}\)

c

\(X Y_{2.5}\)

d

\(X_{1.5} Y_2\)

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Q25
PYQ

The oxide that shows magnetic property is:

[JEE Main 2021, 18 Mar (Shift 2)]

a

\( \mathrm{MgO} \)

b

\( \mathrm{Na}_{2} \mathrm{O} \)

c

\( \mathrm{SiO}_{2} \)

d

\( \mathrm{Mn}_{3} \mathrm{O}_{4} \)

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Q26
PYQ

Which of the following expressions is correct in case of a \(CsCl\) unit cell (edge length 'a')?

[JEE Main 2023, 15 Apr (Shift 1)]

a

\(r _{ Cs ^{+}}+ r _{ Cl ^{-}}=\frac{ a }{\sqrt{2}}\)

b

\(r _{ Cs+ }+ r _{ Cl }= a\)

c

\(r _{ Cs ^{+}}+ r _{ Cl ^{-}}=\frac{\sqrt{3}}{2} a\)

d

\(r _{ Cs ^{+}}+ r _{ Cl ^{-}}=\frac{ a }{2}\)

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Q27
PYQ

A sample of a metal oxide has formula \({M}_{0.83}{O}_{1.00}\). The metal M can exist in two oxidation states +2 and +3 . In the sample of \({M}_{0.83}{O}_{1.00}\), the percentage of metal ions existing in +2 oxidation state is_____ %

(Report your answer after dividing by 10) (nearest integer)

a

4

b

5

c

6

d

7

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