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A cell of emf \(E\) is connected across an external resistance \(R\). When current ' \(I\) ' is drawn from the cell, the…

Q1

A cell of emf \(E\) is connected across an external resistance \(R\). When current ' \(I\) ' is drawn from the cell, the potential difference across the electrodes of the cell drops to \(V\). The internal resistance ' \(r\) ' of the cell is

a

\(\left(\frac{E-V}{E}\right) R\)

b

\(\left(\frac{E-V}{R}\right)\)

c

\(\frac{( E - V ) R }{ I }\)

d

\(\left(\frac{E-V}{V}\right) R\)

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