4-nitrotoluene is treated with \({\mathrm{Br}}_{2}\) to get compound P which is reduced with Sn and HCl to get Compound …
4-nitrotoluene is treated with \({\mathrm{Br}}_{2}\) to get compound P which is reduced with Sn and HCl to get Compound Q, then Q is diazotized and the product is treated with phosphinic acid to get R is oxidized with alkaline \({\mathrm{KMnO}}_{4}\) to get the final product
(JEE mains memory based shift-1 23/01/2025)
2-Bromo Benzoic acid
1.4-Nitrotoluene + Br₂: Bromination at the meta position forms 2-Bromo-4-nitrotoluene (Compound P).
2.P + Sn/HCl: Reduction of the nitro group forms 2-Bromo-4-aminotoluene (Compound Q).
3.Q + NaNO₂/HCl: Diazotization forms a diazonium salt.
4.Diazonium salt + H₃PO₄: Forms 2-Bromo-4-hydroxybenzene (Compound R).
5.R + KMnO₄ (alkaline): Oxidation forms 2-Bromo-4-carboxybenzoic acid (final product).
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