If \(\left[\begin{array}{cc}x+y & 2 \\ 5 & x y\end{array}\right]=\left[\begin{array}{ll}6 & 2 \\ 5 & 8\e…
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If \(\left[\begin{array}{cc}x+y & 2 \\ 5 & x y\end{array}\right]=\left[\begin{array}{ll}6 & 2 \\ 5 & 8\end{array}\right]\), then the value of \(\left(\frac{24}{x}+\frac{24}{y}\right)\) is :
✓ Correct answer: d)
18
Explanation
Given: \(\left[\begin{array}{cc}x+y & 2 \\ 5 & x y\end{array}\right]=\left[\begin{array}{ll}6 & 2 \\ 5 & 8\end{array}\right]\)
Corresponding elements must be equal,
\(x+y=6\), \(xy=8\)
Now, \(\frac{24}{x}+\frac{24}{y}=24\left(\frac{1}{x}+\frac{1}{y}\right)\)
\(=24\left(\frac{x+y}{xy}\right)\\ =24\times \frac{6}{8}\\ =18\)
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