\({\mathrm{CH}}_{3}-\mathrm{C}\equiv \mathrm{CH}\overset{\mathrm{Pd}/\mathrm{C}}{\underset{{\mathrm{H}}_{2}}{\to }}\math…
Q1 FREE PREVIEW
\({\mathrm{CH}}_{3}-\mathrm{C}\equiv \mathrm{CH}\overset{\mathrm{Pd}/\mathrm{C}}{\underset{{\mathrm{H}}_{2}}{\to }}\mathrm{A}\overset{(\mathrm{i}){\mathrm{O}}_{3}}{\underset{(\mathrm{ii})\mathrm{Zn},{\mathrm{H}}_{2}\mathrm{O}}{\to }}\mathrm{B}+\mathrm{C}\)
Products B and C are :
Memory Based Question 28/Jan/25 Evening shift
✓ Correct answer: a)
Ethanal and formaldehyde
Explanation
Step 1: Hydrogenation (H₂/Pd-C)
Propyne (CH₃-C≡CH) undergoes partial hydrogenation to form propene (CH₃-CH=CH₂).
Step 2: Ozonolysis (O₃/Zn, H₂O)
Ozonolysis cleaves the C=C bond in propene, producing:
- Ethanal (CH₃CHO)
- Formaldehyde (HCHO)
Thus, the correct answer is: (A) Ethanal and Formaldehyde.
Practice more Board Chemistry PYQs
See every question on Aldehydes, Ketones and Carboxylic Acids, or browse the full Board question bank.
See all questions on Aldehydes, Ketones and Carboxylic Acids →