Direction ratios of a vector parallel to line $\frac{x-1}{2}=-y=\frac{2 z+1}{6}$ are :

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Correct answer: d) $2,-1,3$. Given equation of the line is $ \frac{x-1}{2}=-y=\frac{2 z+1}{6} $ $ \Rightarrow \frac{x-1}{2}=\frac{y-0}{-1}=\frac{2\left(z+\frac{1}{2}\right)}{6} $ $ \Rightarrow \frac{x-1}{2}=\frac{y-0}{-1}=\frac{z+\frac{1}{2}}{3}$ The direction ratios of the line are $(2,-1,3)$.

Direction ratios of a vector parallel to line \(\frac{x-1}{2}=-y=\frac{2 z+1}{6}\) are :

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