BoardPhysics

Oscillations

10 Board Physics previous year questions on Oscillations — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ

A particle is executing simple harmonic motion with time period 2 s and amplitude 1 cm . If D and d are the total distance and displacement covered by the particle in 12.5 s , then \(\frac{D}{d}\) is

a

10

b

25

c

\(\frac{15}{4}\)

d

\(\frac{16}{5}\)

✓ Correct answer: b)

25

Explanation

The period T is 2 seconds, so the number of complete cycles in 12.5 seconds is:

\(n=\frac{12.5}{2}=6.25\text{ cycles. }\)

In one full cycle, the particle moves a distance of 4 A (since it goes from +A to -A and back to +A).
So, in 6.25 cycles, the total distance covered is:

\(D=6.25\times 4A=6.25\times 4\times 1=25cm\)

Since after 6 full cycles, the particle returns to its starting position, it only moves A in the last incomplete cycle.
Therefore, the displacement is d =1 cm.

\(\frac{D}{d}=\frac{25}{1}=25\)

Q2
PYQ

A simple pendulum doing small oscillations at a place R height above earth surface has time period of \({T}_{1}=4\mathrm{s}\). \({T}_{2}\) would be it's time period if it is brought to a point which is at a height 2R from earth surface. Choose the correct relation [R = radius of earth]:

a

\(2{T}_{1}=3{T}_{2}\)

b

\(2{T}_{1}={T}_{2}\)

c

\({T}_{1}={T}_{2}\)

d

\(3{T}_{1}=2{T}_{2}\)

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Q3
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Two particles of same mass are performing SHM vertically with two different springs of spring constants \(K_1\) and \(K_2\). If amplitude of both is same. Find ratio of the maximum speed of two particles.

a

\(\sqrt{\frac{K_1}{K_2}}\)

b

\(\sqrt{K_1 K_2}\)

c

\(\sqrt{\frac{K_2}{K_1}}\)

d

\(\sqrt{\frac{K_1+K_2}{K_1-K_2}}\)

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Q4
PYQ

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Time period of a simple pendulum is longer at the top of a mountain than that at the base of the mountain.
Reason (R): Time period of a simple pendulum decreases with increasing value of acceleration due to gravity and vice-versa.
In the light of the above statements, choose the most appropriate answer from the options given below :

[JEE Main 2025, 29 Jan (Shift 1)]

a

Both (A) and (R) are true and (R) is the correct explanation of (A)

b

Both (A) and (R) are true but (R) is not the correct explanation of (A)

c

(A) is true but (R) is false

d

(A) is false but (R) is true

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Q5
PYQ

The measured value of the length of a simple pendulum is \(20 \mathrm{~cm}\) with \(2 \mathrm{~mm}\) accuracy. The time for 50 oscillations was measured to be 40 seconds with 1 second resolution. From these measurements, the accuracy in the measurement of acceleration due to gravity is \(\mathrm{N} \%\). The value of \(\mathrm{N}\) is:

[JEE Main 2024, 31 Jan (Shift 2)]

a

4

b

8

c

6

d

5

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Q6
PYQ

A spring-block system has a time period of 2 seconds. If D is the total distance traveled by the block and \(d\) is the displacement of the block in 12.5 seconds, find the ratio D/d.(Shift I - Memory Based)

a

12

b

25

c

20

d

10

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Q7
PYQ

The two-dimensional motion of a particle, described by \(\vec{\mathrm{r}}=(\hat{i}+2\hat{j})\mathrm{Acos}\omega t\) is a/an:
A. parabolic path
B. elliptical path
C. periodic motion
D. simple harmonic motion

Choose the correct answer from the options given below :

[Re-NEET 2024]

a

B, C and D only

b

A, B and C only

c

A, C and D only

d

C and D only

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Q8
PYQ

A spring-block system has a time period of 2 seconds. If D is the total distance traveled by the block and \(d\) is the displacement of the block in 12.5 seconds, find the ratio D/d.(Shift I - Memory Based)

a

12

b

25

c

20

d

10

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Q9
PYQ

A body is executing simple harmonic motion with frequency \( n \) , the frequency of its potential energy is:

a

\( 2 \mathrm{n} \)

b

\( 3 \mathrm{n} \)

c

\( 4 \mathrm{n} \)

d

\( \mathrm{n} \)

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Q10
PYQ

A particle executing simple harmonic motion with amplitude A has the same potential and kinetic energies at the displacement :

a

\(2\sqrt{\mathrm{A}}\)

b

\(\frac{\mathrm{A}}{2}\)

c

\(\frac{\mathrm{A}}{\sqrt{2}}\)

d

\(\mathrm{A}\sqrt{2}\)

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