Inverse Trigonometric Functions

Given: The walvength of a moving paticle is given by de Broglie relation:

$\mathrm{\lambda } = \frac{\mathrm{h}}{\mathrm{p}}$ where h is Planck's constant and p is the linear momentum.

If an electron and a proton have the same wavelength $\mathrm{\lambda }.$

$\Rightarrow \frac{h}{p_e}= \frac{h}{p_p}$

$\Rightarrow p_e = p_p$

Hence, both have the same momentum.

Given: The walvength of a moving paticle is given by de Broglie relation:

$\mathrm{\lambda } = \frac{\mathrm{h}}{\mathrm{p}}$ where h is Planck's constant and p is the linear momentum.

If an electron and a proton have the same wavelength $\mathrm{\lambda }.$

$\Rightarrow \frac{h}{p_e}= \frac{h}{p_p}$

$\Rightarrow p_e = p_p$

Hence, both have the same momentum.

Given: The walvength of a moving paticle is given by de Broglie relation:

$\mathrm{\lambda } = \frac{\mathrm{h}}{\mathrm{p}}$ where h is Planck's constant and p is the linear momentum.

If an electron and a proton have the same wavelength $\mathrm{\lambda }.$

$\Rightarrow \frac{h}{p_e}= \frac{h}{p_p}$

$\Rightarrow p_e = p_p$

Hence, both have the same momentum.