BoardMaths

Inverse Trigonometric Functions

9 Board Maths previous year questions on Inverse Trigonometric Functions — options free on every question; 1 include the answer & explanation free, the rest unlock with PYQ Pass.

Q1 FREE PREVIEW
PYQ

The number of solutions of \({\text{tan}}^{−1}4x+{\text{tan}}^{−1}6x=\frac{\pi }{6}\), where \(−\frac{1}{2\sqrt{6}}

[JEE Main 2026, 22 Jan (Shift 1)]

a

0

b

2

c

1

d

3

✓ Correct answer: c)

1

Explanation

\({\text{tan}}^{−1}4x+{\text{tan}}^{−1}6x=\frac{\pi }{6}\)

\(\Rightarrow {\text{tan}}^{−1}\left(\frac{4x+6x}{1-24{x}^{2}}\right)=\frac{\pi }{6}\)

\(\Rightarrow \frac{10x}{1−24{x}^{2}}=\frac{1}{\sqrt{3}}\)

\(\Rightarrow 24{x}^{2}+10\sqrt{3}x−1=0\)

\(x=\frac{−10\sqrt{3}\pm \sqrt{300+96}}{48}\)

\(x=\frac{\sqrt{396}−10\sqrt{3}}{48}\)

Only 1 solution in \(\left(−\frac{1}{2\sqrt{6}},\frac{1}{2\sqrt{6}}\right)\)

Q2
PYQ

If \(f(x)=16\left(\left(\sec ^{-1} x\right)^2+\left(\operatorname{cosec}^{-1} x\right)^2\right)\) then the sum of max. and min. value of \(f(x)\) is (22 Jan, Shift I, Memory Based)

a

\(22{\pi }^{2}\)

b

\(20{\pi }^{2}\)

c

\(2{\pi }^{2}\)

d

None of these

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Q3
PYQ

If \(\mathrm{y}={\sin }^{-1}x,-1\leq x\leq 0\), then the range of y is:

a

\(\left(\frac{-\pi }{2},0\right)\)

b

\(\left[\frac{-\pi }{2},0\right]\)

c

\(\left[\frac{-\pi }{2},0\right)\)

d

\(\left(\frac{-\pi }{2},0\right]\)

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Q4
PYQ

If \(\mathrm{y}={\sin }^{-1}x,-1\leq x\leq 0\), then the range of \(y\) is:

a

\(\left(\frac{-\pi }{2},0\right)\)

b

\(\left[\frac{-\pi }{2},0\right]\)

c

\(\left[\frac{-\pi }{2},0\right)\)

d

\(\left(\frac{-\pi }{2},0\right]\)

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Q5
PYQ

(ii) The principal value of \({\sin }^{-1}\left(-\frac{1}{2}\right)\) is -

a

\(\frac{\pi }{6}\)

b

\(-\frac{\pi }{6}\)

c

\(\frac{4\pi }{3}\)

d

\(\frac{2\pi }{3}\)

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Q6
PYQ

The principal value of \({\sin }^{-1}\left(\frac{1}{\sqrt{2}}\right)\)is

a

\(-\frac{\pi }{4}\)

b

\(\frac{\pi }{3}\)

c

\(\frac{\pi }{6}\)

d

\(\frac{\pi }{4}\)

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Q7
PYQ

Assertion (A) : Domain of \(\mathrm{y}={\cos }^{-1}(\mathrm{x})\) is \([-1,1]\).
Reason (R) : The range of the principal value branch of \(\mathrm{y}={\cos }^{-1}(x)\) is \([0,\pi ]-\left\{\frac{\pi }{2}\right\}\).

a

Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).

b

Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of the Assertion (A).

c

Assertion (A) is true, but Reason (R) is false.

d

Assertion (A) is false, but Reason (R) is true.

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Q8
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Direction : Two statements are given one labelled Assertion (A) and the other labelled Reason (R). Select the correct answer from the following options :
Assertion (A) : Domain of \(\mathrm{y}={\cos }^{-1}(\mathrm{x})\) is \([-1,1]\).
Reason (R) : The range of the principal value branch of \(\mathrm{y}={\cos }^{-1}(x)\) is \([0,\pi ]-\left\{\frac{\pi }{2}\right\}\).

a

Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).

b

Both Assertion (A) and Reason (R) are true and Reason (R) is not the correct explanation of the Assertion (A).

c

Assertion (A) is true, but Reason (R) is false.

d

Assertion (A) is false, but Reason (R) is true.

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Q9
PYQ

\({\tan }^{-1}\sqrt{3}-{\sec }^{-1}(-2)\) is equal to

a

\(\pi\)

b

\(-\frac{\pi }{3}\)

c

\(\frac{\pi }{3}\)

d

\(\frac{2\pi }{3}\)

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