Hydrocarbons

• I true: Neopentane, C(CH₃)₄, is highly symmetric; all 12 hydrogens are equivalent → only one monosubstituted derivative.

• II true: Its high symmetry improves packing, giving a higher melting point than n-pentane.
  Thus both statements are correct → (B)

Baeyer's reagent is a cold, dilute solution of potassium permanganate (KMnO₄).

A. Propene $\left(C{H}_3-CH=C{H}_2\right)$ does not show geometrical isomerism as one of the double-bonded carbon atom has two identical hydrogen atoms.
B. Correct statement
C. Correct statement
D. 2-Methylbut-2-ene $\left(C{H}_{3}C\left(C{H}_3\right)\right.$ $=CHC{H}_3$ ) does not show geometrical isomerism because one of the double bonded carbon atom has two identical methyl groups.
E. Trans-isomers have higher symmetry and better packing efficiency, leading to a higher melting point than cis-isomers.

Trans isomers have higher symmetry compared to cis isomers, hence they are tightly packed leading to higher melting point compared to the cis isomers.

Trans isomers have higher symmetry compared to cis isomers, hence they are tightly packed leading to higher melting point compared to the cis isomers.